(1+x)^2=1.02

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Solution for (1+x)^2=1.02 equation:



(1+x)^2=1.02
We move all terms to the left:
(1+x)^2-(1.02)=0
We add all the numbers together, and all the variables
(x+1)^2-(1.02)=0
We add all the numbers together, and all the variables
(x+1)^2-1.02=0
We move all terms containing x to the left, all other terms to the right
(x+1)^2=1.02

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